2x^2-4x+4-4+12=0

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Solution for 2x^2-4x+4-4+12=0 equation: 



2x^2-4x+4-4+12=0

We add all the numbers together, and all the variables

2x^2-4x+12=0

a = 2; b = -4; c = +12;
Δ = b2-4ac
Δ = -42-4·2·12
Δ = -80
Delta is less than zero, so there is no solution for the equation

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